10.0.0.1:80 > 10.0.0.2:52209 [PSH, ACK] Seq=1 Ack=1 Win=17376 Len=2
10.0.0.1:80 > 10.0.0.2:52209 [PSH, ACK] Seq=3 Ack=1 Win=17376 Len=48
10.0.0.1:80 > 10.0.0.2:52209 [PSH, ACK] Seq=51 Ack=1 Win=17376 Len=1
10.0.0.1:80 > 10.0.0.2:52209 [PSH, ACK] Seq=52 Ack=1 Win=17376 Len=2
10.0.0.1:80 > 10.0.0.2:52209 [PSH, ACK] Seq=54 Ack=1 Win=17376 Len=48
10.0.0.2:52209 > 10.0.0.1:80 [ACK] Seq=1 Ack=1 Win=7896 Len=0
10.0.0.2:52209 > 10.0.0.1:80 [ACK] Seq=1 Ack=3 Win=7896 Len=0
10.0.0.2:52209 > 10.0.0.1:80 [ACK] Seq=1 Ack=3 Win=7896 Len=0
10.0.0.2:52209 > 10.0.0.1:80 [ACK] Seq=1 Ack=3 Win=7896 Len=0
10.0.0.2:52209 > 10.0.0.1:80 [ACK] Seq=1 Ack=3 Win=7896 Len=0
10.0.0.1:80 > 10.0.0.2:52209 [ACK] Seq=3 Ack=1 Win=17376 Len=48
Considerando o trecho de captura acima apresentado, julgue o item a seguir.
Os segmentos presentes caracterizam tráfego em volume.